Off topic: Mathematician needed to solve a problem Thread poster: xxxBoschi

xxxBoschi Germany Local time: 16:33 German to Italian + ...
with x = R
I have to find out the function:
x... x... x = 6
that is:
0 ... 0 ... 0 = 6
1... 1.... 1 = 6
2....2.....2 = 6
and so on
Can anyone help me?
Kind regards   
Attila Piróth France Local time: 16:33 Member English to Hungarian + ... Please be more specific  Feb 1, 2008 
Boschi wrote:
with x = R
I have to find out the function:
x... x... x = 6
that is:
0 ... 0 ... 0 = 6
1... 1.... 1 = 6
2....2.....2 = 6
and so on
Can anyone help me?
Kind regards
So, you have to find a function that has one unknown, x, and the value of the function is always 6?
Here is a possibility:
f(x) = 6 * sgn [x*x+1], where sgn is the sign function; sgn[y]=1 for positive numbers y, and y=(x*x+1) is positive for all real numbers x.
Attila
[Módosítva: 20080201 09:09]   
Mathematician needed to solve a problem  Feb 1, 2008 
Boschi wrote:
with x = R
I have to find out the function:
x... x... x = 6
that is:
0 ... 0 ... 0 = 6
1... 1.... 1 = 6
2....2.....2 = 6
and so on
Can anyone help me?
Kind regards
2+2+2=6;
3*33=6;
Roland   
There's an infinite number of answers  Feb 1, 2008 
If you allow all the math operators in place of the ...s
One example:
x **2 * 6 / x / x
where
**2 is "squared"
* is multiplication
/ is division
HOWEVER, very few (if any) of them will work for x = zero (this one doesn't and I can't think of one that does right now)).
T.   
Niels Stephan Germany Local time: 16:33 Member (2009) English to German Wrong "language" (and I thought proz.com was a language platform)  Feb 1, 2008 
The problem isn't stated in the language of a mathematician, so no mathematician will be able to help you out.
What is R? Rational numbers?
What do the ... stand for?
So please rephrase.
@Roland: What about the line with the zeros?   
factorials, and power of 0  Feb 1, 2008 
the factorial of 3 is 6,
(1+1+1)! = 3! = 3 x 2 x 1 = 6
Any number to the power of 0 (except 0 itself) is 1. So this solution will work for all numbers, except 0.
However, zero factorial(0!) is also 1.
so for zero, a solution would be
(0! + 0! + 0!)! = 6   
Attila Piróth France Local time: 16:33 Member English to Hungarian + ... 0 to the 0th power = 1  Feb 1, 2008 
Cilian O'Tuama wrote:
the factorial of 3 is 6,
(1+1+1)! = 3! = 3 x 2 x 1 = 6
Any number to the power of 0 (except 0 itself) is 1. So this solution will work for all numbers, except 0.
However, zero factorial(0!) is also 1.
so for zero, a solution would be
(0! + 0! + 0!)! = 6
Yes, factorial can be very useful.
But 0 to the 0th power is one, by definition (or convention, if you prefer), so you can use that one, too.
Attila   
Attila Piróth wrote:
But 0 to the 0th power is one, by definition (or convention, if you prefer), so you can use that one, too.
Attila
Not everyone would agree. Is it not undefined, just like any number divided by zero?
[Edited at 20080201 13:40]   
Attila Piróth France Local time: 16:33 Member English to Hungarian + ...
Cilian O'Tuama wrote:
Attila Piróth wrote:
But 0 to the 0th power is one, by definition (or convention, if you prefer), so you can use that one, too.
Attila
Not everyone would agree. Is it not undefined, just like any number divided by zero?
[Edited at 20080201 13:40]
You're right, there is not such a unanimity as for 0 factorial:
If the exponent is zero, some authors define 0 ^ 0=1, whereas others leave it undefined, as discussed below.
http://en.wikipedia.org/wiki/Exponentiation#Powers_of_zero
Attila   
ivo abdman Indonesia Local time: 22:33 English to Indonesian + ...
1/0" is a paradox; in a way that "0/1" is not. Nothing can be divided by zero. If one approaches the formula from the positive side, it would appear that the answer is an infinite positive value. If one approaches the formula from the negative side, the opposite is true. Thus, anything divided by zero is simultaneously positive and negative infinity. "One over Zero" is a paradox in another way too, in a way that transcends mere arithmetic. One is something, and Zero is nothing. The fact that the universe holds something over nothing, that it prefers to exist, rather than not exist, is fundamentally absurd. No being can ever come to deserve its own birth. 1/0 is a cry out against mere logic and efficiency. Stuff exists. All existence, all truth, cannot be ultimately justified: it can only be described, explained, and enjoyed.
1/0 is illogical. 1/0 is irrational. 1/0 is impossible. 1/0 is transcendentally unfair.
1/0 is true. Deal with it.
[Edited at 20080201 17:15]   
colemh Local time: 10:33 English to Spanish + ...
(Cos(0)+Cos(0)+Cos(0))!=6 (Cosine(0)=1)
(1+1+1)!=6
2+2+2=6
(3*3)3=6
√4+√4+√4=6 (square root(4)=2)
(5/5)+5=6
6+66=6
(7/7)+7=6
√8+√8+√8=6 (cube root(8)=2)
√9*√9√9=6 (square root(9)=3)
[Edited at 20080204 02:21]   
V N Ganesh Local time: 21:03 Japanese to English + ...
Boschi wrote:
with x = R
I have to find out the function:
x... x... x = 6
that is:
0 ... 0 ... 0 = 6
1... 1.... 1 = 6
2....2.....2 = 6
and so on
Can anyone help me?
Kind regards
R+(62R)+RR+R=6 where R=x=0,1,2...   