Off topic: Mathematician needed to solve a problem Thread poster: Boschi (X)
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Boschi (X) 
Germany
Local time: 02:34
German to Italian
+ ...
with x = R
I have to find out the function:
x... x... x = 6
that is:
0 ... 0 ... 0 = 6
1... 1.... 1 = 6
2....2.....2 = 6
and so on
Can anyone help me?
Kind regards
| | | | Attila Piróth
France
Local time: 02:34
Member
English to Hungarian
+ ...
| Please be more specific | Feb 1, 2008 |
Boschi wrote:
with x = R
I have to find out the function:
x... x... x = 6
that is:
0 ... 0 ... 0 = 6
1... 1.... 1 = 6
2....2.....2 = 6
and so on
Can anyone help me?
Kind regards
So, you have to find a function that has one unknown, x, and the value of the function is always 6?
Here is a possibility:
f(x) = 6 * sgn [x*x+1], where sgn is the sign function; sgn[y]=1 for positive numbers y, and y=(x*x+1) is positive for all real numbers x.
Attila
[Módosítva: 2008-02-01 09:09]
| | | | Roland Hofmann-Tikkanen (X)
Finland
Local time: 03:34
Finnish to German
| Mathematician needed to solve a problem | Feb 1, 2008 |
Boschi wrote:
with x = R
I have to find out the function:
x... x... x = 6
that is:
0 ... 0 ... 0 = 6
1... 1.... 1 = 6
2....2.....2 = 6
and so on
Can anyone help me?
Kind regards
2+2+2=6;
3*3-3=6;
Roland
| | | | | There's an infinite number of answers | Feb 1, 2008 |
If you allow all the math operators in place of the ...s
One example:
x **2 * 6 / x / x
where
**2 is "squared"
* is multiplication
/ is division
HOWEVER, very few (if any) of them will work for x = zero (this one doesn't and I can't think of one that does right now)).
T.
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Niels Stephan
Germany
Local time: 02:34
Member (2009)
English to German
| Wrong "language" (and I thought proz.com was a language platform) | Feb 1, 2008 |
The problem isn't stated in the language of a mathematician, so no mathematician will be able to help you out.
What is R? Rational numbers?
What do the ... stand for?
So please rephrase.
@Roland: What about the line with the zeros?
| | | | | factorials, and power of 0 | Feb 1, 2008 |
the factorial of 3 is 6,
(1+1+1)! = 3! = 3 x 2 x 1 = 6
Any number to the power of 0 (except 0 itself) is 1. So this solution will work for all numbers, except 0.
However, zero factorial(0!) is also 1.
so for zero, a solution would be
(0! + 0! + 0!)! = 6
| | | | Attila Piróth
France
Local time: 02:34
Member
English to Hungarian
+ ...
| 0 to the 0th power = 1 | Feb 1, 2008 |
Cilian O'Tuama wrote:
the factorial of 3 is 6,
(1+1+1)! = 3! = 3 x 2 x 1 = 6
Any number to the power of 0 (except 0 itself) is 1. So this solution will work for all numbers, except 0.
However, zero factorial(0!) is also 1.
so for zero, a solution would be
(0! + 0! + 0!)! = 6
Yes, factorial can be very useful.
But 0 to the 0th power is one, by definition (or convention, if you prefer), so you can use that one, too.
Attila
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Attila Piróth wrote:
But 0 to the 0th power is one, by definition (or convention, if you prefer), so you can use that one, too.
Attila
Not everyone would agree. Is it not undefined, just like any number divided by zero?
[Edited at 2008-02-01 13:40]
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Attila Piróth
France
Local time: 02:34
Member
English to Hungarian
+ ...
Cilian O'Tuama wrote: Attila Piróth wrote:
But 0 to the 0th power is one, by definition (or convention, if you prefer), so you can use that one, too.
Attila Not everyone would agree. Is it not undefined, just like any number divided by zero? [Edited at 2008-02-01 13:40]
You're right, there is not such a unanimity as for 0 factorial:
If the exponent is zero, some authors define 0 ^ 0=1, whereas others leave it undefined, as discussed below.
http://en.wikipedia.org/wiki/Exponentiation#Powers_of_zero
Attila
| | | | ivo abdman
Indonesia
Local time: 07:34
English to Indonesian
+ ...
1/0" is a paradox; in a way that "0/1" is not. Nothing can be divided by zero. If one approaches the formula from the positive side, it would appear that the answer is an infinite positive value. If one approaches the formula from the negative side, the opposite is true. Thus, anything divided by zero is simultaneously positive and negative infinity. "One over Zero" is a paradox in another way too, in a way that transcends mere arithmetic. One is something, and Zero is nothing. The fact that the... See more 1/0" is a paradox; in a way that "0/1" is not. Nothing can be divided by zero. If one approaches the formula from the positive side, it would appear that the answer is an infinite positive value. If one approaches the formula from the negative side, the opposite is true. Thus, anything divided by zero is simultaneously positive and negative infinity. "One over Zero" is a paradox in another way too, in a way that transcends mere arithmetic. One is something, and Zero is nothing. The fact that the universe holds something over nothing, that it prefers to exist, rather than not exist, is fundamentally absurd. No being can ever come to deserve its own birth. 1/0 is a cry out against mere logic and efficiency. Stuff exists. All existence, all truth, cannot be ultimately justified: it can only be described, explained, and enjoyed.
1/0 is illogical. 1/0 is irrational. 1/0 is impossible. 1/0 is transcendentally unfair.
1/0 is true. Deal with it.
[Edited at 2008-02-01 17:15] ▲ Collapse
| | | | colemh
Local time: 19:34
English to Spanish
+ ...
(Cos(0)+Cos(0)+Cos(0))!=6 (Cosine(0)=1)
(1+1+1)!=6
2+2+2=6
(3*3)-3=6
√4+√4+√4=6 (square root(4)=2)
(5/5)+5=6
6+6-6=6
-(7/7)+7=6
√8+√8+√8=6 (cube root(8)=2)
√9*√9-√9=6 (square root(9)=3)
[Edited at 2008-02-04 02:21]
| | | | V N Ganesh
Local time: 06:04
Japanese to English
+ ...
Boschi wrote:
with x = R
I have to find out the function:
x... x... x = 6
that is:
0 ... 0 ... 0 = 6
1... 1.... 1 = 6
2....2.....2 = 6
and so on
Can anyone help me?
Kind regards
R+(6-2R)+R-R+R=6 where R=x=0,1,2...
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