passband voltage sensitivity

French translation: sensibilité en tension dans la bande passante

GLOSSARY ENTRY (DERIVED FROM QUESTION BELOW)
English term or phrase:passband voltage sensitivity
French translation:sensibilité en tension dans la bande passante
Entered by: Tony M

14:24 Oct 20, 2015
English to French translations [PRO]
Tech/Engineering - Media / Multimedia / music reproduction
English term or phrase: passband voltage sensitivity
Many personal digital music players have a limited output for driving high-quality headphones—which may have a higher impedance, a lower passband voltage sensitivity or both.
Aurélie Labrosse
United Kingdom
sensibilité en tension dans la bande passante
Explanation:
To be honest, the use of 'passband' in EN is questionable; unless there is some specific reason given elsewhere in your surrounding context, there is no real justification for qualifying it as 'passband' — the 'out-of-band' voltage sensitivity would be largely irrelevant in the context given here. Sound to me a bit like techno marketing speak — though it might be helpful to know just WHAT it is lower or higher than?

The meaning is, however, clear enough: the voltage sensitivity (usually the only parameter of interest in this sort of context, since current sensitivity is usually irrelevant for even quite medium impedance systems) across the passband (= frequency response)

In other words, they are talking about the in-band sensitivity — the only useful parameter here, though the out-of-band sensitivity is unlikely to be a very meaningful criterion.

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Note added at 2 heures (2015-10-20 17:13:20 GMT)
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I think what they're seeking to say is that "Many personal digital music players have a limited output..." but ours have more than enough output to spare.

The point is, higher-impedance headphones will require a greater output voltage to drive them (higher impedance will mean less current, and since Power = I [current] × V [voltage], the higher the impedance, the higher the voltage that will be needed to produce the same (electrical) power.

Conversely, if the headphones have lower sensitivity (and voltage sensitivity is simply the most usual parameter quoted) , they will require a higher (electrical) power input in order to produce the same (mechanical = sound) power output.
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Tony M
France
Local time: 17:03
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Selected automatically based on peer agreement.
4 KudoZ points were awarded for this answer



Summary of answers provided
3 +3sensibilité en tension dans la bande passante
Tony M
4une moindre sensibilité à la tension de la bande passante
HERBET Abel


Discussion entries: 2





  

Answers


1 hr   confidence: Answerer confidence 4/5Answerer confidence 4/5
une moindre sensibilité à la tension de la bande passante


Explanation:
suggéré

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Note added at 1 hr (2015-10-20 15:52:41 GMT)
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http://forums.futura-sciences.com/physique/159183-sensibilit...

HERBET Abel
Local time: 17:03
Native speaker of: French
PRO pts in category: 8
Notes to answerer
Asker: Merci !

Login to enter a peer comment (or grade)

2 hrs   confidence: Answerer confidence 3/5Answerer confidence 3/5 peer agreement (net): +3
sensibilité en tension dans la bande passante


Explanation:
To be honest, the use of 'passband' in EN is questionable; unless there is some specific reason given elsewhere in your surrounding context, there is no real justification for qualifying it as 'passband' — the 'out-of-band' voltage sensitivity would be largely irrelevant in the context given here. Sound to me a bit like techno marketing speak — though it might be helpful to know just WHAT it is lower or higher than?

The meaning is, however, clear enough: the voltage sensitivity (usually the only parameter of interest in this sort of context, since current sensitivity is usually irrelevant for even quite medium impedance systems) across the passband (= frequency response)

In other words, they are talking about the in-band sensitivity — the only useful parameter here, though the out-of-band sensitivity is unlikely to be a very meaningful criterion.

--------------------------------------------------
Note added at 2 heures (2015-10-20 17:13:20 GMT)
--------------------------------------------------

I think what they're seeking to say is that "Many personal digital music players have a limited output..." but ours have more than enough output to spare.

The point is, higher-impedance headphones will require a greater output voltage to drive them (higher impedance will mean less current, and since Power = I [current] × V [voltage], the higher the impedance, the higher the voltage that will be needed to produce the same (electrical) power.

Conversely, if the headphones have lower sensitivity (and voltage sensitivity is simply the most usual parameter quoted) , they will require a higher (electrical) power input in order to produce the same (mechanical = sound) power output.

Tony M
France
Local time: 17:03
Specializes in field
Native speaker of: Native in EnglishEnglish
PRO pts in category: 101
Grading comment
Selected automatically based on peer agreement.
Notes to answerer
Asker: Merci !


Peer comments on this answer (and responses from the answerer)
agree  Antoine Dequidt: Perfect remark about marketing!
4 mins
  -> Merci, Antoine ! En effet, c'est trop souvent le cas, n'est-ce pas ?

agree  kashew
12 mins
  -> Thanks, J! ;-)

agree  Savvas SEIMANIDIS: kalispéra Tony !
3 hrs
  -> Efharisto, Savvas!
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