French: Bis (diphénylamino-2,5)-triazinyl-1,3,5-amino-4-4,4'- stilbène-disulfonate-2,2'English translation: 2,5-bis(diphenylamino)-1,3,5-triazinyl-4,4'-diaminostilbene-2,2'-disulfonate
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| GLOSSARY ENTRY (DERIVED FROM QUESTION BELOW) | | French term or phrase: | Bis (diphénylamino-2,5)-triazinyl-1,3,5-amino-4-4,4'- stilbène-disulfonate-2,2' | | English translation: | 2,5-bis(diphenylamino)-1,3,5-triazinyl-4,4'-diaminostilbene-2,2'-disulfonate
| | Entered by: | Zareh Darakjian Ph.D. |
| Options: - Contribute to this entry |
French to English translations [PRO] Science - Chemistry; Chem Sci/Eng / optical brighteners | | French term or phrase: Bis (diphénylamino-2,5)-triazinyl-1,3,5-amino-4-4,4'- stilbène-disulfonate-2,2' | Is this:
Sodium bis(2,5-diphenylamino)-1,3,5-triazinyl-4-4,4'-amino-2,2'-stilbene-disulfonate?
Am I even getting close?
Many thanks to all who've been helping with my 'chemical encounters' - some of these chemicals are a lot more complex than my mind.
In the unlikely event I am actually right, do copy it into the answer box and grab yourself some points!
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| | Clarification request(s) and responseZareh Darakjian Ph.D.: 8:41pm Jan 12, 2005: Gabrielle: I am assumiong the sodium was part of the text which was not included in the question.. - Zareh Darakjian Ph.D.: 8:42pm Jan 12, 2005: Well, I will be taking typing lessons: *assuming* - Gabrielle Lyons (asker): 9:06pm Jan 13, 2005: Thanks, Zareh. Yes, "de sodium" must have got chopped off the end. Question box is too short for these chemicals.
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| | 2,5-bis(diphenylamino)-1,3,5-triazinyl-4,4'-diaminostilbene-2,2'-disulfonate | Explanation: I believe it should be diamino. I will give you a reference of a relaed compound. There
you will see the diamino groups (NH2) in 4,4' positions.
-------------------------------------------------- Note added at 10 hrs 44 mins (2005-01-12 19:55:46 GMT) --------------------------------------------------
www.google.com/search?hl=en&lr=&q=triazinyl+derivatives+of+...
-------------------------------------------------- Note added at 10 hrs 48 mins (2005-01-12 19:59:08 GMT) --------------------------------------------------
/www.google.com/search?hl=en&q=triazinyl+derivatives+of+stil...
choose the first listing and go to page 9.
-------------------------------------------------- Note added at 10 hrs 50 mins (2005-01-12 20:01:00 GMT) --------------------------------------------------
www.google.com/search?hl=en&q=triazinyl+derivatives+of+stil...
-------------------------------------------------- Note added at 10 hrs 51 mins (2005-01-12 20:02:42 GMT) --------------------------------------------------
This is better, I think. A structure related to the one you have is on page 9 of the first
listing (the middle structure). There you will see the stilbene, which is two phenyls connected by a =CH= bridge, and the two amino groups in the 4,4\' positions and also
the sulfonates!
-------------------------------------------------- Note added at 10 hrs 58 mins (2005-01-12 20:09:16 GMT) --------------------------------------------------
In chemical nomenclature, as we do in most languages with repspect to saying our name,
we saye the first name first, and the family name last. In chemistry, the first name is the
brnaches (substituents). Here the family name is *stilbene*. It comes last. So you can see
that sulfonate, and amido groups have perched on this stilbene ring at positions 1,1\' (not
mentioned) and 4,4\', respectively!
-------------------------------------------------- Note added at 11 hrs 0 min (2005-01-12 20:11:11 GMT) --------------------------------------------------
What\'s different in the case of the compound that we are beholding here, is that there
are to additional huge substituentes, namely, two (bis) phenylamino groups. Once you
add those, to the structure that you see in the reference above, *voila*, you have what
you want.
-------------------------------------------------- Note added at 11 hrs 1 min (2005-01-12 20:12:01 GMT) --------------------------------------------------
Where are these additional huge substituents on the stilbene parent structure? They are
at the 2 and 5 positions!
-------------------------------------------------- Note added at 11 hrs 2 mins (2005-01-12 20:13:59 GMT) --------------------------------------------------
*say*, *branches* and *substituents* of course!
-------------------------------------------------- Note added at 12 hrs 50 mins (2005-01-12 22:01:41 GMT) --------------------------------------------------
Of course, what we have here is the salt of the sulfonic acid, which means the SOOH group
has lost its H^+ and become a SOO- group, and the charge is presumably balanced by
a Na^+.
-------------------------------------------------- Note added at 12 hrs 54 mins (2005-01-12 22:05:38 GMT) --------------------------------------------------
It\'s actually O=S=O O=S=O
| going to |
OH O^-
sulfonic acid going to sulfonate |
| Selected response from: Zareh Darakjian Ph.D. United States
| Note from asker to answerer| 4 KudoZ points were awarded for this answer |
|
10 hrs confidence:   |
| 2,5-bis(diphenylamino)-1,3,5-triazinyl-4,4'-diaminostilbene-2,2'-disulfonate
Explanation: I believe it should be diamino. I will give you a reference of a relaed compound. There
you will see the diamino groups (NH2) in 4,4' positions.
-------------------------------------------------- Note added at 10 hrs 44 mins (2005-01-12 19:55:46 GMT) --------------------------------------------------
www.google.com/search?hl=en&lr=&q=triazinyl+derivatives+of+...
-------------------------------------------------- Note added at 10 hrs 48 mins (2005-01-12 19:59:08 GMT) --------------------------------------------------
/www.google.com/search?hl=en&q=triazinyl+derivatives+of+stil...
choose the first listing and go to page 9.
-------------------------------------------------- Note added at 10 hrs 50 mins (2005-01-12 20:01:00 GMT) --------------------------------------------------
www.google.com/search?hl=en&q=triazinyl+derivatives+of+stil...
-------------------------------------------------- Note added at 10 hrs 51 mins (2005-01-12 20:02:42 GMT) --------------------------------------------------
This is better, I think. A structure related to the one you have is on page 9 of the first
listing (the middle structure). There you will see the stilbene, which is two phenyls connected by a =CH= bridge, and the two amino groups in the 4,4\' positions and also
the sulfonates!
-------------------------------------------------- Note added at 10 hrs 58 mins (2005-01-12 20:09:16 GMT) --------------------------------------------------
In chemical nomenclature, as we do in most languages with repspect to saying our name,
we saye the first name first, and the family name last. In chemistry, the first name is the
brnaches (substituents). Here the family name is *stilbene*. It comes last. So you can see
that sulfonate, and amido groups have perched on this stilbene ring at positions 1,1\' (not
mentioned) and 4,4\', respectively!
-------------------------------------------------- Note added at 11 hrs 0 min (2005-01-12 20:11:11 GMT) --------------------------------------------------
What\'s different in the case of the compound that we are beholding here, is that there
are to additional huge substituentes, namely, two (bis) phenylamino groups. Once you
add those, to the structure that you see in the reference above, *voila*, you have what
you want.
-------------------------------------------------- Note added at 11 hrs 1 min (2005-01-12 20:12:01 GMT) --------------------------------------------------
Where are these additional huge substituents on the stilbene parent structure? They are
at the 2 and 5 positions!
-------------------------------------------------- Note added at 11 hrs 2 mins (2005-01-12 20:13:59 GMT) --------------------------------------------------
*say*, *branches* and *substituents* of course!
-------------------------------------------------- Note added at 12 hrs 50 mins (2005-01-12 22:01:41 GMT) --------------------------------------------------
Of course, what we have here is the salt of the sulfonic acid, which means the SOOH group
has lost its H^+ and become a SOO- group, and the charge is presumably balanced by
a Na^+.
-------------------------------------------------- Note added at 12 hrs 54 mins (2005-01-12 22:05:38 GMT) --------------------------------------------------
It\'s actually O=S=O O=S=O
| going to |
OH O^-
sulfonic acid going to sulfonate
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