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shear stress

Spanish translation: esfuerzo de corte

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GLOSSARY ENTRY (DERIVED FROM QUESTION BELOW)
English term or phrase:shear stress
Spanish translation:esfuerzo de corte
Entered by: Andrea Bullrich
Options:
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- Include in personal glossary

01:41 Oct 4, 2000
English to Spanish translations [PRO]
Tech/Engineering
English term or phrase: shear stress
construction - arquitecture
Mikel Cimarro
ESFUERZO DE CORTE
Explanation:
VER ESTE TEXTO TECNICO :
Esfuerzo de corte ( Shear stress)= F/A
Rata de corte (Shear rate ) = v/x
La viscosidad absoluta es igual a la relación entre el esfuerzo de corte y la rata de corte: Viscosidad absoluta = Shear stress/shear rate
Selected response from:

Telesforo Fernandez
Local time: 09:15
Grading comment
4 KudoZ points were awarded for this answer

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Summary of answers provided
na +1esfuerzo cortante
Marijke Singer
naESFUERZO DE CORTETelesforo Fernandez
naSee below
Alejandra Villarroel


  

Answers


46 mins peer agreement (net): +1
esfuerzo cortante


Explanation:
Hi,
From Beigbeder's Diccionario técnico inglés - español
and
web site: http://www.unav.es/estructuras/docencia/estructuras1/c2/

Good luck!

Marijke Singer
United Kingdom
Local time: 03:45
Native speaker of: Native in EnglishEnglish, Native in SpanishSpanish
PRO pts in pair: 574

Peer comments on this answer (and responses from the answerer)
agree  MMT
4802 days
  -> ¡Muchas gracias!
Login to enter a peer comment (or grade)

50 mins
See below


Explanation:
Resistencia al corte
Resistencia en cizalla

Buena suerte, María Alejandra


    Reference: http://eurodic.ip.lu
Alejandra Villarroel
Chile
Local time: 00:45
Native speaker of: Spanish
PRO pts in pair: 428
Login to enter a peer comment (or grade)

1 hr
ESFUERZO DE CORTE


Explanation:
VER ESTE TEXTO TECNICO :
Esfuerzo de corte ( Shear stress)= F/A
Rata de corte (Shear rate ) = v/x
La viscosidad absoluta es igual a la relación entre el esfuerzo de corte y la rata de corte: Viscosidad absoluta = Shear stress/shear rate


Telesforo Fernandez
Local time: 09:15
PRO pts in pair: 266
Login to enter a peer comment (or grade)




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