https://www.proz.com/kudoz/english-to-spanish/medical-general/2216105-x-g-%3D-times-gravity.html

x g = times gravity

21:00 Oct 24, 2007
English to Spanish translations [PRO]
Medical - Medical (general) / clinical trials
English term or phrase: x g = times gravity
I do not have more context
Monica


Summary of answers provided
3 +1G x = Número de Embarazos
Diego Cruz, MD
3x g = multiplicado por la gravedad
hugocar


Discussion entries: 1





  

Answers


1 hr   confidence: Answerer confidence 3/5Answerer confidence 3/5 peer agreement (net): +1
G x = Número de Embarazos


Explanation:
Depende mucho del contexto (por eso el nivel de confianza de la respuesta), pero se utiliza así cuando se elabora la historia clínica en los antecedentes gineco-obstétricos. P.ej. puede aparecer como G3 P2 A1 esto quiere decir que tuvo 3 embarazos, 2 partos y 1 aborto. o G0 P0 A0 significa que no ha estado embarazada

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Note added at 1 hr (2007-10-24 22:05:57 GMT)
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Preimplantation genetic diagnosis for cancer predisposition syndromes
c.3921 3925del (exon 15) G0P0A0. 28. Objection to TOP ... c.4093 4096del (exon 15) G0P0A0. 33. Concomitant subfertility and. objection to TOP ...
doi.wiley.com/10.1002/pd.1708 - Similar pages

Example sentence(s):
  • Preimplantation genetic diagnosis for cancer predisposition syndromes
Diego Cruz, MD
United States
Local time: 23:11
Specializes in field
Native speaker of: Native in SpanishSpanish
PRO pts in category: 282

Peer comments on this answer (and responses from the answerer)
agree  David Russi: el error es que gravity debería decir gravida = embarazos
54 mins
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31 mins   confidence: Answerer confidence 3/5Answerer confidence 3/5
x g = multiplicado por la gravedad


Explanation:
No hay contexto que facilite la comprensión, pero creo que es una opción válida.

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Note added at 54 mins (2007-10-24 21:54:36 GMT)
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También x g = multiplicado por la fuerza de la gravedad.

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Note added at 1 hr (2007-10-24 22:19:48 GMT)
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No me dí cuenta que la pregunta está referida al tema Medicina. Yo creí que se trataba de una pregunta sobre física. Por lo tanto, estoy de acuerdo con la respuesta de Diego, más abajo.

hugocar
Local time: 23:11
Native speaker of: Native in SpanishSpanish
PRO pts in category: 20
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